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Reptile [31]
3 years ago
9

If x2=7 what is a value of x? A.√7 B.3.5 C.√49 D.14

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

x = sqrt(7) or x = -sqrt(7) thus of the choices you have A:

Step-by-step explanation:

Solve for x:

x^2 = 7

Take the square root of both sides:

Answer: x = sqrt(7) or x = -sqrt(7)

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Laura drove 638 miles in 11 hours at the same rate how long would it take her to drive 406 miles
shusha [124]

Answer:

Step-by-step explanation:

This is a d = rt problem; but since it is linear, then proportions will work too. Set up the proportion with miles on top and hours on the bottom:

\frac{miles}{hrs}:

Then put the numbers in where they go, keeping in mind that miles goes with miles and hours goes with hours in the ratios, and that our unknown is time (hours):

\frac{miles}{hrs}:\frac{638}{11}=\frac{406}{x} and cross multiply to solve:

638x = 4466 so

x = 7 hrs

6 0
2 years ago
Somebody help me out please
Marina86 [1]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Anna bought a skirt on sale at a clothing store for $54.48. The original price of this skirt was $72.64. She is interested in a
Basile [38]
$115.45 This should be the correct answer. Hope this help need brainlest.
6 0
3 years ago
Read 2 more answers
Add. What is the sum (2 * 10 exponent 16) + ( 7 * 10 exponent 16) in scientific notation
Roman55 [17]

Answer:

9 * 10^16

Step-by-step explanation:

 2 * 10^16

+7 * 10^16

 9 * 10^16

5 0
3 years ago
a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

6 0
3 years ago
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