Answer:
The probability that more than 6 samples are needed to have 2 mutations is P=0.866.
Step-by-step explanation:
This question can be analized with the binomial distribution.
We need to calculate the probability that more of 6 samples are needed to have 2 samples with mutations.
This is equal to the proability of taking 2 samples and getting one mutation or less.
Then we have a binomial distribution with n=6 and p=0.11:
Answer:
1.
2.
3. correct
4.
Step-by-step explanation:
When dividing a monomial by another monomial, we divide the coefficients and apply the quotient law of exponents, x m ÷ x n = x m – n to the variables. If both the monomials have negative coefficients, the negative signs cancel out and the answer so obtained will be having a positive coefficient only.
For example, the binomial 2x +4 can be multiplied by the monomial 4x so that (2x) (4x) equals 8x2 and 4·4x equals 16x, using the distributive property. Therefore, (2x +4) (4x) equals 8x2 + 16x.Mar 15, 2016
Use the Quotient Property. When we divide monomials with more than one variable, we write one fraction for each variable. Use fraction multiplication. Simplify and use the Quotient Property.