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My name is Ann [436]
3 years ago
15

What is Golden ratios?Plz help me​

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0
In mathematics, two quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities. Expressed algebraically, for quantities a and b with a > b > 0,
blondinia [14]3 years ago
5 0

Answer:

Golden ratio, also known as the golden section, golden mean, or divine proportion, in mathematics, the irrational number (1 + Square root of√5)/2, often denoted by the Greek letter ϕ or τ, which is approximately equal to 1.618.

Step-by-step explanation:

In the picture.

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Hiii please help! i’ll give brainliest if you give a correct answer tysm!
Aleks [24]

Answer:

B) 3 1/3

Step-by-step explanation:

To divide the fractions, simply follow these steps.

First, flip the second fraction, so that the numerator is the denominator, and the denominator is the numerator. Change the division sign into a multiplication:

(2/3)/(1/5) = (2/3) * (5/1)

Next, multiply straight across:

(2/3) * (5/1) = (2 * 5)/(3 * 1) = 10/3

Finally, simplify. Change the improper fraction into a mixed:

10/3 = 3/3 + 3/3 + 3/3 + 1/3 =  3 1/3

B) 3 1/3 is your answer.

~

8 0
3 years ago
Read 2 more answers
Write the equation of a line perpendicular to 3x + 4y = 9 that passes through (8, - 4)
Arisa [49]

keeping in mind that perpendicular lines have <u>negative reciprocal</u> slopes, let's find the slope of 3x + 4y = 9, by simply putting it in slope-intercept form.


\bf 3x+4y=9\implies 4y=-3x+9\implies y=-\cfrac{3x+9}{4}\implies y=\stackrel{slope}{-\cfrac{3}{4}}x+\cfrac{9}{4} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{4}{3}}\qquad \stackrel{negative~reciprocal}{+\cfrac{4}{3}}\implies \cfrac{4}{3}}


so we're really looking for the equation of a line whose slope is 4/3 and runs through 8, -4.


\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{-4})~\hspace{10em} slope =  m\implies \cfrac{4}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{4}{3}(x-8) \implies y+4=\cfrac{4}{3}x-\cfrac{32}{3} \\\\\\ y=\cfrac{4}{3}x-\cfrac{32}{3}-4\implies y=\cfrac{4}{3}x-\cfrac{44}{3}

5 0
3 years ago
A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false
kvasek [131]
I have to go with True because a Rhombus is a Square. 
3 0
3 years ago
Read 2 more answers
PLZ HELP ME I AM TIMED HELP PLZ​
ladessa [460]

Answer:

c

ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

6 0
3 years ago
PLEASE ANYONE!!!
siniylev [52]
Constant but not linear.
5 0
3 years ago
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