9 - 7 3/5
9 - 38/5
38/5- 9/1
29/4 or 7 1/4
(A)
we are given
we can use vertical line test
If the vertical line intersects at two points
then this is not the function
because a function can not have two outputs for same input
we get graph as
so, this is not function
(B)
we are given
we can use vertical line test
If the vertical line intersects at two points
then this is not the function
because a function can not have two outputs for same input
we get graph as
so, this is not function
So how you do scientific notation is, however many places you move the decimal point to the left is the number that you put in the power. For example, Mercury's mass is 330,000,000,000,000,000,000,000. You move the decimal point 23 places to the left to get 3.3 x 10^23. ( ^ means power. The little number that is next to the 10)
Now according to the question, the mass of Jupiter is 5.8 x 10^3 multiplied by 3.3 x 10^23 (5,800 x 330,000,000,000,000,000,000,000).
The answer to part A is,
1,941,000,000,000,000,000,000,000,000
Then, 3.2 x 10^2(X)=5.8 x 10^3 x 3.3 x 10^23
I don't know if you know how to do algebra, but this is very simple to solve. All you do is divide bolth sides of the equation by 3.2 x 10^2 leaving X (Earths mass) on the left.
For the right side need to divide 320 by 1,941,000,000,000,000,000,000,000,000. This will be the answer to part B
Hopefully this was helpful enough for you to show your work. Good luck : )
Answer: 0
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Explanation:
When we multiply 0 by any number, we get 0 as a result
x*0 = 0
0*x = 0
for any number x.
The number 0 is rational since we can write it as a fraction of two integers
0 = 0/1
If Daniel were to correct his statement to say "multiply by any <u>nonzero</u> rational number", then his statement would be correct that the result is irrational.
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Extra info:
Here's a proof showing why Daniel's claim is correct if we consider nonzero rational numbers
Let p be a nonzero rational number, so p = a/b for integers a,b where neither a or b are zero
Let q be an irrational number. We cannot write q as a ratio of two integers
The claim is that p*q is irrational. For now let's assume the opposite. So assume p*q is rational. This means p*q = r/s for integers r,s
This would be the same as (a/b)*q = r/s which solves to q = (r/s)*(b/a) = (rb)/(sa) making q rational, but that contradicts the fact we made q irrational earlier.
Therefore, the assumption p*q is rational cannot be the case, and p*q must be irrational.
-9/10
thats the correct answer but you dont have that choice on your number line so???
