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Vilka [71]
3 years ago
15

A principal gathered data about the distance, in miles, that his teachers and bus drivers live from the school. The box plots be

low show these data. Based on the box plots, which statement is true? *
well i think is C or D
Mathematics
1 answer:
choli [55]3 years ago
7 0

Answer:

Step-by-step explanation:

It is C

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Which complex number does not lie on the line segment
mihalych1998 [28]
Im pretty sure its B or -2i
8 0
3 years ago
You are rolling two dice. When the two numbers (1-6) come up, you multiply the numbers
Tasya [4]

Answer:

1/4 probability of getting a product that isn't divisible by 2.

Step-by-step explanation:

These are all the possible outcomes

1 x 1 = 1    2 x 1 = 2    3 x 1 = 3     4 x 1 = 4     5 x 1 = 5      6 x 1 = 6

1 x 2 = 2   2 x 2 = 4   3 x 2 = 6     4 x 2 = 8    5 x 2 = 10    6 x 2 = 12

1 x 3 = 3  2 x 3 = 6    3 x 3 = 9     4 x 3 = 12   5 x 3 = 15   6 x 3 = 18

1 x 4 = 4   2 x 4 = 8   3 x 4 = 12     4 x 4 = 16   5 x 4 = 20  6 x 4 = 24

1 x 5 = 5   2 x 5 = 10  3 x 5 = 15   4 x 5 = 20  5 x 5 = 25  6 x 5 = 30

1 x 6 =  6   2 x 6 = 12  3 x 6 = 18   4 x 6 = 24   5 x 6 = 30  6 x 6 = 36

All of the outcomes that aren't divisible by 2 are in bold

There are 9 out of 36 possible outcomes that aren't divisible by 2

9/36 = 1/4

8 0
4 years ago
What is the value of the expression 3 (5to the 3rd power) + 4t to the 2nd power when s = 5 and t = 3?
SIZIF [17.4K]

Answer:

137

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help! need these answers filled in for school asap
vampirchik [111]

Answer:

Given : JKLM is a rectangle.

Prove: JL ≅ MK

Since, by the definition of rectangle all angles of rectangles are right angle.

Thus, In rectangle JKLM,

∠ JML and  ∠KLM are right angles.

⇒ ∠ JML ≅ ∠KLM

Since, JM ≅ KL   (Opposite sides of rectangles are congruent)

ML ≅ ML  ( Reflexive )

Thus, By SAS congruence postulate,

Δ JML ≅ Δ KLM

⇒ JL ≅ MK  ( because corresponding parts of congruent triangles are congruent)

Hence proved.

3 0
3 years ago
How to derive: f(w)=ln(cos(w-1))
postnew [5]
The word you're looking for is "differentiate", not "derive".

\dfrac{\mathrm d}{\mathrm dw}\ln(\cos(w-1))=\dfrac{\frac{\mathrm d}{\mathrm dw}\cos(w-1)}{\cos(w-1)}=\dfrac{-\sin(w-1)\frac{\mathrm d}{\mathrm dw}(w-1)}{\cos(w-1)}=-\dfrac{\sin(w-1)}{\cos(w-1)}=-\tan(w-1)
3 0
4 years ago
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