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Citrus2011 [14]

2 years ago

12

The manager of a local ice cream shop wants to learn more about the distribution of the ages of his customers. After keeping tra

ck of customer ages for one week, he creates the following histogram

1 answer:

Scilla [17]2 years ago

7 0

Ayo we need more information you know you can post pictures right?

You might be interested in

Can sombody explain this and give me the answer please and thank you

Furkat [3]

Answer: 54 Points

Step-by-step explanation:

They have 16 wins, one win is three points so 16 times 3, 48.

They have 6 losses, one loss is one point to 1 times 6, 6.

Add 6 and 48

Then you get an answer of 54

8 0

2 years ago

Read 2 more answers

What are the number 2,3,5,7,11,13,17,19, and 23

rjkz [21]

They are all prime numbers,because you can only multiply them by 1.

6 0

2 years ago

I came up the answer as 57. I will attach my note, can you check?

ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

$\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}$

so, we need a function that relates, angle, adjancent side and opposite side

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

replace

$\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}$

Step 2

BED

again, we have a rigth triangle,then let

$\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}$

so, we need a function that relates; angle, hypotenuse and adjacent side

$\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}$

replace.

$\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}$

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

$\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}$

so, the answer is 19

I hop

4 0

9 months ago

The surface area of the figure below is 50.80m^2 True or False

solong [7]

For this case we have that by definition, the surface area of a cone is given by:

$SA = \pi * r * s + \pi * r ^ 2$

Where:

A: It's the radio

s: It's the slant

Substituting according to the data we have:

$SA = \pi * 2.1 * 5.6 + \pi * (2.1) ^ 2\\SA = 36.9264 + 13.8474\\SA = 50.7738 \ m ^ 2$

If we round:

$SA = 50.8 \ m ^ 2$

Answer:

True

8 0

3 years ago

What is the answer I need help

KATRIN_1 [288]

I know what the answer is

6 0

2 years ago