Hello there
the answer to your question is adaptations
thank you
Answer:
DDWw x Ddww
DdWw x DDww
DDWw x DDww
Explanation:
D for tallness
d for dwarfness
W for violet
w for white
For Parental Plants that has
tall, violet x tall, white
The representation will be
DDWW × DDww (We the apply the mendelian crossing)
This will yield offsprings with the following trait
DDDD × DwDw
DDDD × DwDw
DWDW x WwWw
DdWw x ddww
Ddww x ddWw
DdWw x DdWw
DDWw x ddww
From the above Offsprings
1/2 tall, white and 1/2 tall, violets offspring are
DDWw x Ddww
DdWw x DDww
DDWw x DDww
"Eukaryote" roughly translates as "truly nucleated" and refers to organisms with a membrane-bound nucleus.
Such membrane-bound organelles are thought to have arisen via the invagination of the cell's own plasma membrane.
Other organelles such as the mitochondria and the chloroplast are believed to have once existed as separate organisms, but which were engulfed by other cells, forming a symbiotic relationship.
The cell membrane is semi-permeable, kind of like a filter to let some molecules in and keep larger molecules out
<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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