Find the value of x. I added an attachment please help I don't need an explanation.

Mathematics

2 answers:

mel-nik [20]3 years ago

8 0

69 degrees

i know you don’t want an explanation but the answer asks for more characters but they just add up to 180 degrees

juin [17]3 years ago

4 0

Answer:

Step-by-step explanation:

(x+54+57)=180

x=69

You might be interested in

PLEASE HELP ME WITH MY GEOMETRY WORK!!! I DONT UNDERSTAND IT AND I DONT KNOW WHY!!!?

IgorLugansk [536]

Answer: im so confused

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Chelsea and her family are taking a road trip. they leave their home in flowery branch Georgia and drive to Nashville which is 1

sukhopar [10]

(x,y) ... (X-163, Y+125) Which ever direction it is, you apply it to the rule.

7 0

2 years ago

Find the solutions of the quadratic equation 3x^2-4x+4=0

julia-pushkina [17]

Answer:

2.3

Step-by-step explanation: if your finding the decimal 2.3 will be your answer if not then sorry

8 0

2 years ago

What is 0.9 10 times as much as what

BabaBlast [244]

9x1 at least I think

4 0

3 years ago

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago