Answer:

Step-by-step explanation:
So we have the two functions:

And we want to find:

This is the same thing as:

So, substitute h(x) into g(x):

Distribute the negative:

And we're done!
So:

Here, to make your day a little better<3
All the triangles are isosceles meaning that they have to sides that are equal
Answer: The integer is +6
Step-by-step explanation:
This is because it say TWICE so double that and 6 added twice is 12.
SO the integer is 6 not -6 because they would cancel out and you would end up with a 0
Hope that helps
Answer:
the answer to the question is 57.... please give me brainliest
Step-by-step explanation:
