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2 years ago

An artist mixes paint to make new colors.

Mathematics

1 answer:

Tems11 [23]2 years ago

7 0

Answer:

The artist can make six batches of orange paint and it remains one cup of yellow paint

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Amount of red paint for one batch of orange paint = 1/3 of a cup

Amount of yellow paint for one batch of orange paint= 1/3 of a cup

Amount of red paint available = 2 cups

Amount of yellow paint available = 3 cups

2. How many batches of orange paint can she make?

2 cups of red paint = 6/3 = 6 batches of orange paint

3 cups of yellow paint = 9/3 = 6 batches and it remains one cup of yellow paint

The artist can make six batches of orange paint and it remains one cup of yellow paint

Step-by-step explanation:

You might be interested in

A sporting goods stores sells footballs, basketballs, and volleyballs. A football costs $35, a basketball costs

wlad13 [49]

Answer:

The number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

Step-by-step explanation:

Consider the provided information.

A football costs $35, a basketball costs $25 and a volleyball costs $15.

Let F represents the football, B represents the basketball and V represents the volleyball.

On a given day, the store sold 5 times as many footballs as volleyballs.

$F=5V$ ......(1)

They brought in a total of $3750 that day,

$35F+25B+15V=3750$ ......(2)

The money made from basketballs alone was 4 times the money.

$25B=4(15V)$ ......(3)

By equation 1, 2 and 3.

$35(5V)+4(15V)+15V=3750$

$250V=3750$

$V=15$

Substitute the value of V in equation 1 and 3.

$F=5(15)=75$

$25B=4(15\times 15)\\B=36$

Hence, the number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

8 0

3 years ago

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t

skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that $\mu = 273, \sigma = 100$

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 30, s = \frac{100}{\sqrt{30}}$

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}$

$Z = 0.88$

$Z = 0.88$ has a p-value of 0.8106

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}$

$Z = -0.88$

$Z = -0.88$ has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 50, s = \frac{100}{\sqrt{50}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}$

$Z = 1.13$

$Z = 1.13$ has a p-value of 0.8708

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}$

$Z = -1.13$

$Z = -1.13$ has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 100, s = \frac{100}{\sqrt{100}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}$

$Z = -1.6$

$Z = -1.6$ has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0

2 years ago

A tailor earns (12y² + y – 35) pesos for working (3y – 5) hours. How much does he earn per hour?

Natalka [10]

Answer:

4y+7

Step-by-step explanation:

(12y² + y – 35)/(3y – 5)

=(3y-5)(4y+7)/(3y-5) (factorization)

=4y + 7

Hope this helped!

4 0

2 years ago

Based on the side lengths given (a, b, and c), which triangles are right triangles?

Mekhanik [1.2K]

Answer:

B & C

Step-by-step explanation:

Use the Pythagorean Theorem: a^2 + b^2 = c^2

A) 18^2 + 24^2 = 2,088 | 42^2 = 1,764 [NOT A]

B) 33^2 +56^2 = 4,225 | 65^2 = 4,225 [B IS CORRECT]

C) 19^2 + 180^2 = (32,761) = 181^2 = (32,761) [C IS CORRECT]

D) 3^2 + 4^2 = 25 | 7^2 = 49 [NOT D]

I hope this helped you ! In return, please deem this the most brainliest answer.

7 0

3 years ago

Find the slope of the line.

Nady [450]

Answer:

The answer is -2

Step-by-step explanation:

It goes down 2 and the line is to the left, meaning its negative :)

7 0

3 years ago