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MAVERICK [17]
3 years ago
14

Expression that has a value of 2.472.

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer 4.6/5. 20

Step-by-step explanation: . lizcocch. Beginner. 2 answers. 11 people helped. The second expression, (16-8)x2+4, has a value of 20.

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7 0
3 years ago
(24 – 16x) = - (18x – 27)<br> How many solutions does the equation have?
Leni [432]

Answer:

One Solution

Step-by-step explanation:

If You get an answer with one x and one y then there is only one solution to the system

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WhT what is the average of 120,90,95,100
Anarel [89]
101.25 , you add all the numbers up and divide by how many numbers set contains ... so 405/4=101.25
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Help and yelp! Asap!
OlgaM077 [116]
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3 years ago
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The perimeter of a rectangle is 320mm. If its length increases by 10mm and its breadth decreases by 10mm then it its area will b
wariber [46]

Answer:

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

Step-by-step explanation:

Given : The perimeter of a rectangle is 320 mm. If its length increases by 10 mm and its breadth decreases by 10 mm then it its area will be 32 less.

To find : Calculate the length and breadth of the original rectangle ?

Solution :

The area of the rectangle is A=L\times B

Let the length of the rectangle be 'x'

The breadth of the rectangle be 'y'

The area is A=xy

Now, length increases by 10 mm i.e. L=x+10

breadth decreases by 10 mm i.e. B=y-10

The new area is A_n=(x+10)(y-10)

According to question,

A-A_n=32

xy-(x+10)(y-10)=32 ......(1)

The perimeter of a rectangle is 320 mm.

i.e. P=2(L+B)

320=2(x+y)

x+y=160

x=160-y .....(2)

Substitute the value of y from eqn (2) in (1),

y(160-y)-(160-y+10)(y-10)=32

160y-y^2-(170-y)(y-10)=32

160y-y^2-(180y-1700-y^2)=32

160y-y^2-180y+1700+y^2=32

1700-20y=32

20y=1732

y=\frac{1732}{20}

y=86.6

Substitute in (2),

x=160-86.6

x=73.4

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

4 0
3 years ago
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