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DIA [1.3K]
2 years ago
14

What additional information is needed to prove the triangles are congruent by SAS ?

Mathematics
1 answer:
Wittaler [7]2 years ago
5 0

Answer: Its EB≅CB

Step-by-step explanation: I took the test

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[98 points to anyone who answers all] Use the diagram below to answer the following questions.
Marysya12 [62]

Answer: #10 is right angles


Step-by-step explanation: because that is the sign for a right angle


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3 years ago
Translate from the English form to algebraic form. The square of the difference of 2x plus y and 8 A. (2x + y)2 + 82 B. 82 – (2x
Alex
I believe that it is C. ((2x + y) - 8)2
8 0
4 years ago
A player of a video game is confronted with a series of opponents and has an 80% probability of defeating each one. Success with
Vikentia [17]

Answer:

(a) The PMF of <em>X</em> is: P(X=k)=(1-0.20)^{k-1}0.20;\  k=0, 1, 2, 3....

(b) The probability that a player defeats at least two opponents in a game is 0.64.

(c) The expected number of opponents contested in a game is 5.

(d) The probability that a player contests four or more opponents in a game is 0.512.

(e) The expected number of game plays until a player contests four or more opponents is 2.

Step-by-step explanation:

Let <em>X</em> = number of games played.

It is provided that the player continues to contest opponents until defeated.

(a)

The random variable <em>X</em> follows a Geometric distribution.

The probability mass function of <em>X</em> is:

P(X=k)=(1-p)^{k-1}p;\ p>0, k=0, 1, 2, 3....

It is provided that the player has a probability of 0.80 to defeat each opponent. This implies that there is 0.20 probability that the player will be defeated by each opponent.

Then the PMF of <em>X</em> is:

P(X=k)=(1-0.20)^{k-1}0.20;\  k=0, 1, 2, 3....

(b)

Compute the probability that a player defeats at least two opponents in a game as follows:

P (X ≥ 2) = 1 - P (X ≤ 2)

              = 1 - P (X = 1) - P (X = 2)

              =1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20\\=1-0.20-0.16\\=0.64

Thus, the probability that a player defeats at least two opponents in a game is 0.64.

(c)

The expected value of a Geometric distribution is given by,

E(X)=\frac{1}{p}

Compute the expected number of opponents contested in a game as follows:

E(X)=\frac{1}{p}=\frac{1}{0.20}=5

Thus, the expected number of opponents contested in a game is 5.

(d)

Compute the probability that a player contests four or more opponents in a game as follows:

P (X ≥ 4) = 1 - P (X ≤ 3)

              = 1 - P (X = 1) - P (X = 2) - P (X = 3)

              =1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20-(1-0.20)^{3-1}0.20\\=1-0.20-0.16-0.128\\=0.512

Thus, the probability that a player contests four or more opponents in a game is 0.512.

(e)

Compute the expected number of game plays until a player contests four or more opponents as follows:

E(X\geq 4)=\frac{1}{P(X\geq 4)}=\frac{1}{0.512}=1.953125\approx 2

Thus, the expected number of game plays until a player contests four or more opponents is 2.

4 0
3 years ago
There is a box of crackers that has 2/5 of the crackers remaining. If Mrs. Cooper eats 3/10 of the remaining crackers,what fract
Leno4ka [110]

Answer:

1and2and3and4and5and5

6 0
3 years ago
What is the slope of the line?
tamaranim1 [39]

Answer:

-1/2.

Change in y above change in x (don't mix that up)

The first coordinate is 3,-2 the second is 2,-4.

The change is x was -1 . (2-3)

The change in y was 2. (-4-(-2))

7 0
3 years ago
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