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DIA [1.3K]
2 years ago
14

What additional information is needed to prove the triangles are congruent by SAS ?

Mathematics
1 answer:
Wittaler [7]2 years ago
5 0

Answer: Its EB≅CB

Step-by-step explanation: I took the test

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JoAnn is taking a trip to visit her family. After one day of driving, she has traveled 315.2 miles. If JoAnn lives 510 miles fro
Elena L [17]

Answer:

194.8 miles

Step-by-step explanation:

510 - 315.2 = 194.8

Hope this helps!

8 0
2 years ago
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I need to know how to do these asap!!
ludmilkaskok [199]

Answer:


Step-by-step explanation:

y =4/3 x+4

slope intercept form

y = mx+b

the y intercept is 4  (0,4)

and the slope is 4/3  which is change in y over change in x

we go up 4 to the right 3

we can rewrite the slope as -4/-3

so we can go down 4 and to the left 3

this would be point (-3,0)


we have 2 points marked, now draw a line throught them


8 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Which expression was factored completely using the GCF, if the original expression was
Lerok [7]

Answer:

4x(x+2)

Step-by-step explanation:

4 0
3 years ago
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A circle is centered at the origin and contains the point (-6, -8). What is the area of this circle?​
gogolik [260]

Answer:

314 units²

Step-by-step explanation:

Centre of the circle = (0, 0)

Another point on the circle = (-6, -8)

\text {Radius = }\sqrt{(0 - (-6))^2 + (0- (-8))^2}

\text {Radius = }\sqrt{6^2 + 8^2}

\text {Radius = }\sqrt{100}

\text {Radius = }10

Area = π (10)² = 100π = 314 units²

6 0
3 years ago
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