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3 years ago

WhT what is the average of 120,90,95,100

Mathematics

2 answers:

Mamont248 [21]3 years ago

7 0

120+90+95+100= 405
405/4 = 101.25

Anarel [89]3 years ago

3 0

101.25 , you add all the numbers up and divide by how many numbers set contains ... so 405/4=101.25

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Using confidence interval concepts, it is found that:

a) The point estimate is the sample mean.

b) The confidence interval is: $\overline{x} \pm T\frac{s}{n}$

c) If $1411 is between the bounds of the interval yes, otherwise no.

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At item a, it asks to provide a point estimate for the population mean, which is the sample mean $\overline{x}$

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Item b:

In the spreadsheet, it is possible to find the standard deviation for the sample, thus, the t-distribution is used.
The confidence interval will be given by:

$\overline{x} \pm T\frac{s}{n}$

In which:

$\overline{x}$ is the sample mean.
T is the critical value, from the t-distribution, with a two-tailed area of $\frac{1 - 0.95}{2} = 0.025$ and n-1 degrees of freedom.
s is the standard deviation for the sample.
n is the sample size.

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Item c:

We have to check if 1411 is between $\overline{x} - T\frac{s}{n}$ and $\overline{x} +T\frac{s}{n}$ .

If it is, the interval includes the National Average, otherwise, it does not.

A similar problem is given at brainly.com/question/24232455

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<h3>How to apply rigid transformations on a point</h3>

Herein we must apply a rigid transformation into a given point to determine an image. Rigid transformations are transformations applied on a geometric locus such that Euclidean distance is conserved. Dilations are a kind of rigid transformations such that:

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To learn more on dilations: brainly.com/question/13176891

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