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kodGreya [7K]
3 years ago
10

1 pound is closest in weight to which one of the following Metric units of weight? 450 grams 4,500 centigrams 0.045 kilograms 45

,000 milligrams​
Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

0.045 kilograms

Step-by-step explanation:

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Convert:<br> 42 centigrams 6 milligrams =<br> 1<br> milligrams
Naddik [55]

Answer:

centigram is 'bigger.'

Well, if you look on the metric scale it is apparent that 1 mg = 0.1 (or 1/10) cg suggesting that a milligram is the smaller value.

6 0
3 years ago
What is the distance between points (1, 4) and (9, 16)? round to the nearest tenth.
11Alexandr11 [23.1K]

Answer:

14.4 to nearest tenth.

Step-by-step explanation:

By the Pythagoras theorem:-

Distance = √ [ (y2-y1)^2 + (x2-x1)^2 ]   where  the 2 points are (x1,y1) and (x2,y2)

= √ [ (16-4)^2 + (9-1)^2]

= √ 208

= 14.4

6 0
3 years ago
Simplify:(-3x)(-2x5)
Sergio039 [100]

Answer: 30x

Multiply  

−

2

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3

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⋅

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10

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30

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5 0
3 years ago
Read 2 more answers
Please help V'W'is a translation of VW Write the translation rule.
wel

Answer:

(x+11), (y+15)

Step-by-step explanation:

the point v gets translated 11 points to the right, so the translation is x+11.

Point v also gets translated 15 points up, so the translation is y+15

4 0
2 years ago
the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they
horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

\begin{gathered} At\text{ K = 2,  }P^i(-13,\text{ 1)  }\rightarrow\text{   }2(-13,\text{ 1)  }\rightarrow\text{  }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6)  }\rightarrow\text{  }2(-12,\text{ 6)  }\rightarrow\text{   Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3)   }\rightarrow\text{   }2(-10,\text{ 3)  }\rightarrow\text{   R}^{ii}(-20,\text{ 6)} \end{gathered}

5 0
2 years ago
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