Answer: During a chemical reaction, matter cannot be created nor destroyed, matter can change form through physical and chemical changes, but through any of these changes, matter is conserved; even though the matter may change from one form to another, the same number of atoms exists before and after the change takes place.
Explanation: <3
Answer:
![C_2=0.97M](https://tex.z-dn.net/?f=C_2%3D0.97M)
Explanation:
Hello,
In this case, for dilution process, we can notice that the initial moles remain the same once the dilution is completed, therefore, both concentration and volume change considering:
![n_1=n_2\\\\V_1C_1=V_2C_2](https://tex.z-dn.net/?f=n_1%3Dn_2%5C%5C%5C%5CV_1C_1%3DV_2C_2)
In such a way for the given final volume, the resulting concentration is noticed to be:
![C_2=\frac{V_1C_1}{V_2} =\frac{10mL*2.5M}{25.8mL}\\ \\C_2=0.97M](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7BV_1C_1%7D%7BV_2%7D%20%3D%5Cfrac%7B10mL%2A2.5M%7D%7B25.8mL%7D%5C%5C%20%5C%5CC_2%3D0.97M)
This is supported by the fact that the higher the volume the lower the concentration.
Best regards.
Answer is: 0,327 g/l.
<span>Ideal gas law: pV = nRT.
</span><span>V - volume, the amount of space occupied by the gas.
</span><span>p - pressure ,1 atm = 760 torr = 760 mmHg.
</span><span>n - amount of substance.
</span>T - temperature, 273 K = 0°<span>C. T = 25 + 273 = 298K.
</span>R - ideal gas constant,<span> R = 0,08206 L</span>·atm/mol·K<span>.
</span>d(He) = M·p ÷ R·T.
d - density.
M - molar mass.
d(He) = 4g/mol · 2atm ÷ 298K · 0,08206 L·atm/mol·K = 0,327 g/l.