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valkas [14]
3 years ago
15

Determine the hydronium ion concentration Big Points

Chemistry
1 answer:
nalin [4]3 years ago
8 0

Answer:

[H⁺] = 0.00013 M

[OH⁻] = 7.7 × 10⁻¹¹ M

Explanation:

Step 1: Calculate the concentration of H⁺ ions

HCl is a strong acid that dissociates according to the following equation.

HCl ⇒ H⁺ + Cl⁻

The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.

Step 2: Calculate the concentration of OH⁻ ions

We will use the ionic product of water equation.

Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]

[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M

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What is the overall equation for FeCl3(aq) + NH3(aq) + H2O(l)? the overall ionic equation? then the net ionic equation?
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Given: 4Na + O2 → 2Na2O In this chemical reaction, how many moles of Na2O will be produced if 2.90 moles of Na react completely?
crimeas [40]

Since we already have the balanced equation, we know that the ratio between Na:Na_{2}O is 4:2 respectively.

So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:

\frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}}

Then we cross multiply and solve for x:

4x=5.8

x=1.45

Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of Na_{2}O that are produced.

3 0
3 years ago
I wanted known how many of the reaction below is energy released
Tema [17]

Answer:

2

Explanation:

In two reactions energy is released.

1) C₆H₁₂O₆ + 6O₂    →    6H₂O + 6CO₂ + heat

It is cellular respiration reaction.It involves the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂   →    2H₂O  ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

5 0
3 years ago
The elemental analysis of an organic solid extracted from gum arabic (a gummy substance used in adhesives, inks, and pharmaceuti
Evgesh-ka [11]

Answer:

The molar mass of the organic solid is 120.16 g/mol.

The molecular formula of an organic solid is C_4H_8O_4

Explanation:

Let the molecular mass of an organic solid be C_xH_yO_z

\Delta T_b=K_b\times m

Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl  in Kg}}

where,

\Delta T_f =Elevation in boiling point = =1.5^oC

Mass of organic solid= 0.561 g

Mass of diphenyl = 24.9 g = 0.0249 kg (1 kg = 1000 g)

K_b = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}

{\text{Molar mass of solid}}=120.16 g/mol

\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100

Percentage of carbon in an organic solid = 40.0%

40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

x = 4.0

Percentage of hydrogen in an organic solid = 6.7%

6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100

y = 8.0  

Percentage of hydrogen in an organic solid = 6.7%

53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

y = 4.0

The molecular formula of an organic solid is C_4H_8O_4

8 0
3 years ago
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