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alexira [117]
3 years ago
14

Write the equation of a line that is perpendicular to the line; y – 2 = -1/6 (x + 1), and that passes through the given point (–

1, 2).
Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

the equation would be y=6x+8

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Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
What is the 2nd term when -3f^3+9f+6f^4-2 f^2 is arranged in descending order
Pavel [41]
The second term would be -3f^3 because when in descending order it is 
6f^4 - 3f^3 - 2f^2 + 9f 
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%5E%7B0%7D%20x16x%5E%7B0%7D" id="TexFormula1" title="4x^{0} x16x^{0}" alt="4x^{0} x16x^{0}"
statuscvo [17]

Answer:

64

Step-by-step explanation:

its just how it is

8 0
2 years ago
Use elimination to solve the system of equations. <br> x+y=−3 <br> 2x−3y=29
attashe74 [19]

Answer:

(4,-7)

Step-by-step explanation:

7 0
2 years ago
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soldi70 [24.7K]

Answer:

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