We are given the equation:
13x^2 + 6√3 xy + 7y^2 - 16 = 0
Based on the general equation of conic sections:
Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0,
A = 13
B = 6√3
C = 7
D = 0
E = 0
F = -16
So we can find the graph of the equation by solving for the discriminate B^2 - 4AC
B^2 - 4AC, substitute given:
(6^2 * 3) - 4 (13 * 7) = -256
since the discriminate is less than zero, the graph could be a circle or a parabola. In this case, the values of A and C are not equal, then our graph is a parabola.
Hi! for x, you need to do 2x-8 = x+17 and solve, because since b is the midpoint, ab and bc would be congruent.
2x-8 = x+17
1x-8 = 17
1x = 25
x = 25
in order to find ab, you plug in the x into the expression.
ab = 2x-8
ab = 2(25)-8
ab = 42
do the same for bc:
bc = x + 17
bc = 25 + 17
bc = 42
and for ac, combine the two expressions and plug in the value for x.
ac = ab + bc
ac = 2x-8 + x+17
ac = 2(25)-8 + 25+17
ac = 84
i hope this helped! have a good day/night :)
Answer:
The answer is 400 :)
Step-by-step explanation:
hope that helped a little
Yes because fraction wise the denominator that is the smallest is greater. At least that is what I learned
1. If f={(-1,6), (0,3), (2,9), (6,10)} and g={(0,2), (3,7), (12,3)}, what is (fog)(0)?
Bad White [126]
Answer: 9
Step-by-step explanation:
