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agasfer [191]
3 years ago
8

Two groups are going on a trip to the theater. The first group has 30 students in for adult chaperones. The second group has 25

students in for adult chaperones. The cost, in dollars, for each student ticket, S, and each adult ticket, A, can be determined using the system of equations below
Mathematics
1 answer:
Nata [24]3 years ago
7 0

Answer:

$20

Step-by-step explanation:

Two groups are going on a trip to a theater. The first group has 30 students and 4 adult chaperones. The second group has 25 students and 4 adult chaperones. The cost, in dollars, for each student ticket, s, and each adult ticket, a, can be determined using the system of equations below.

30s+4a=720

25s+4a=620

What is the cost for each student ticket?

Solution:

30s+4a=720

(1)

25s+4a=620 (2)

Subtract (2) from (1)

30s - 25s = 720 - 620

5s = 100

Divide both sides by 5

s = 100/5

= 20

s = $20

Substitute the value of s into (1)

30s + 4a = 720

30(20) + 4a = 720

600 + 4a = 720

4a = 720 - 600

4a = 120

a = 120 / 4

= 30

a = $30

Each student tickets cost $20

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Given: Assume y is the population

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\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

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Step-by-step explanation:

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