Check the picture below.
![\textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}asn ~~ \begin{cases} a=apothem\\ n=\stackrel{side's}{number}\\ s=\stackrel{side's}{length}\\[-0.5em] \hrulefill\\ a=7\\ s=8.1\\ n=6 \end{cases}\implies \stackrel{\textit{area of the hexagonal base}}{A=\cfrac{1}{2}(7)(8.1)(6)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dasn%20~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20n%3D%5Cstackrel%7Bside%27s%7D%7Bnumber%7D%5C%5C%20s%3D%5Cstackrel%7Bside%27s%7D%7Blength%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D7%5C%5C%20s%3D8.1%5C%5C%20n%3D6%20%5Cend%7Bcases%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20hexagonal%20base%7D%7D%7BA%3D%5Ccfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{volume of a prism}\\\\ V=Bh ~~ \begin{cases} B=\stackrel{base's}{area}\\ h=height\\[-0.5em] \hrulefill\\ B=\frac{1}{2}(7)(8.1)(6)\\ V=3572.1 \end{cases}\implies 3572.1=\cfrac{1}{2}(7)(8.1)(6)h \\\\\\ 3572.1=170.1h\implies \cfrac{3572.1}{170.1}=h\implies \boxed{21=h}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20prism%7D%5C%5C%5C%5C%20V%3DBh%20~~%20%5Cbegin%7Bcases%7D%20B%3D%5Cstackrel%7Bbase%27s%7D%7Barea%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20B%3D%5Cfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29%5C%5C%20V%3D3572.1%20%5Cend%7Bcases%7D%5Cimplies%203572.1%3D%5Ccfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29h%20%5C%5C%5C%5C%5C%5C%203572.1%3D170.1h%5Cimplies%20%5Ccfrac%7B3572.1%7D%7B170.1%7D%3Dh%5Cimplies%20%5Cboxed%7B21%3Dh%7D)
well, the length of the tunnel is "h", now two 8 meters cars, that's 8+8=16 meters plus a 3 meter connector between them, that's 16 + 3 = 19 meters, can those two cars connected like so fit inside the tunnel? sure thing, "h" can fit 19 meters just fine.
Answer:
a). x = 135°
b). y = 45°
c). z = 67.5°
Step-by-step explanation:
Since sum of interior angles of a regular polygon is represented by,
Sum of interior angles = (n - 2) × 180°
Here n = number of sides
For a regular octagon, n = 8
Sum of interior angles = (8 - 2) × 180° = 1080°
And measure of one interior angles = 
x = 
x = 135°
From the figure attached,
Angle C has been divided in 6 equal parts,
Therefor, m∠ECD =
= 22.5°
Since ∠ECD ≅ ∠CED,
m∠CED = 22.5°
Since m∠E = 135°
m∠FEC = 135 - 22.5 = 112.5°
In ΔFEC,
m∠FEC + m∠ECF + m∠CFE = 180°
112.5 + 22.5 + z = 180
z = 180 - 135
z = 45°
Similarly, in ΔCGF,
m∠CGF + m∠CFG + m∠GCF = 180°
(135 - y)° + (135 - z)° + 22.5° = 180°
270 - (y + z) + 22.5 = 180
292.5 - (y + 45) = 180
247.5 - y = 180
y = 247.5 - 180
y = 67.5°
Answer:
i believe that all of them are right, if they are not please correct me
Step-by-step explanation:
<em>m= y= 2x +4 </em>
<em>p= y= 1x- 1</em>
<em>n= y= -4x </em>
<em>L= y= 0x+ 4</em>
hope this helps!
-8,10 because it crosses the y axis
Answer:
24 with a remainder of 1
Step-by-step explanation
so first you have to bring down the 3 so it is next to the six, and then you divide 36 by 15 and that equals 2. So you right a 2 on top. Then you have to multiply 2 and 15 and that equals 30 so you put a 30 below the 36. After you subtract, it equals 6 then you bring down the 1. Now you divide 61 and 15. The answer is 4 so you put a 4 on top next to the 2. After that you multiply 15 by 4 and that equals 60. You subtract 60 from 61, and you are left with a remainder of 1