Answer:
<em>The sum of 4 consecutive odd number is 80</em>
<em>Let X be the first of these numbers</em>
<em>Then the next odd number is X+2</em>
<em>The third is X+4The fourth is X+6</em>
<em>All of these add up to 80</em>
<em>(X) + (X+2) + (X+4) + (X+6) = 80</em>
<em>Using the commutative and associative laws, let's transform this equation into</em>
<em>(X + X + X + X) + (2 + 4 + 6) = 804X + 12 = 80</em>
<em>Subtract 12 from both sides of the equation gives4X = 68</em>
<em>Divide both sides by 4 gives</em>
<em>X = 17</em>
<em>Going back to the original question:What are the 4 consecutive odd numbers: 17, 19, 21, 23Checking our answer:17 + 19 + 21 + 23 = 80 Correct!</em>
Answer:
- y = 50·3^x
- (2, 450), (3, 1350), (4, 4050), (5, 12150)
Step-by-step explanation:
The problem statement tells you each observed count is 3 times the last one.
__
Expressed as an exponential function with an initial value of 50 and a growth factor of 3, the formula is ...
y = (initial value)×(growth factor)^x
y = 50·3^x
Answer:
5-Cy/r = d
Step-by-step explanation:
C=r(5-d)/y
Multiply each side by y
Cy=r(5-d)/y *y
Cy=r(5-d)
Divide each side by r
Cy/r=r(5-d)/r
Cy/r=(5-d)
Subtract 5 from each side
Cy/r - 5 = 5-d-5
Cy/r - 5 = -d
Multiply by -1
-Cy/r + 5 = d
5-Cy/r = d
Answer:
The last choice: log 25 Over log 8
Step-by-step explanation:
Because the change of base formula says:
log (subscript 8) of 25 = log (25) / log (8)
let log be the Common Log without subscripts
11.11
The '11' before the decimal point is our whole number.
We can write 11 hundredths as 11 over 100.
11/100
So we have:
11 11/100
