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3 years ago

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A shuttle service transports passengers from the airport to local hotels. The vans used have room for up to 6 passengers. Data c

ollected over several years indicate that the number of passengers per trip to the hotels follow the following probabilities.
Passengers: 1 2 3 4 5 6
Probability: 0.20 0.25 0.22 0.13 0.10 0.10

Required:
A van leaves the airport for the local hotels. What is the probability there are at least 4 passengers on board?

1 answer:

sattari [20]3 years ago

4 0

Answer:

Probability = 0.33

Step-by-step explanation:

Passengers: 1 2 3 4 5 6

Probability: 0.20 0.25 0.22 0.13 0.10 0.10

Let No. of passengers = x ; So probability of at least 4 passengers

Prob (x <u>> </u>4) = Prob (x = 4) + Prob (x = 5) + Prob (x = 6)

= 0.13 + 0.10 + 0.10

= 0.33

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The vertex form:

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We have

$y=2x^2+12x+16\to a=2,\ b=12,\ c=16$

Substitute:

$h=\dfrac{-12}{(2)(2)}=\dfrac{-12}{4}=-3$

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A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

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Using the z-distribution and the formula for the margin of error, it is found that:

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$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is of:

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The sample size is <u>n for which M = 0.03</u>, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}$

$\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}$

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Item b:

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$0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}$

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SinA = opposite/hypotenuse

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Checking with your calculator or table of values, A = 54.76 (approximately 55)

Also CosA = adjacent/hypotenuse

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CosA = 0.5750

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