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Oksi-84 [34.3K]
3 years ago
5

What is the area of the shaded segment ?

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0

9514 1404 393

Answer:

  5.1 cm²

Step-by-step explanation:

The area of a segment is given by the formula ...

  A = 1/2r²(α -sin(α)) . . . . . where α is the central angle in radians

For this segment, its area is ...

  A = 1/2(6 cm)²(7π/18 -sin(70°)) ≈ 5.077 cm²

The area of the segment is about 5.1 square centimeters.

_____

The angle is converted to radians by multiplying by π/180°. Then a 70° angle is π(70°/180°) = 7π/18 radians.

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kolbaska11 [484]

Answer:

3/4;4/4

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4 0
3 years ago
Read 2 more answers
Point b lies on the segment ac . Find the length of the segment ac, if ab=7.8 cm, bc=25mm. How many different solutions can this
ladessa [460]

The length of the segment ac is 10.3 cm

<h3>How to determine the length ac?</h3>

The segments are given s:

ab = 7.8cm

bc = 25mm

Point b is located between points a and c.

So, we have:

ac = ab + bc

Substitute known values

ac = 7.8cm + 25mm

Express mm a  cm

ac = 7.8cm + 2.5cm

Evaluate the sum

ac = 10.3 cm

If the point b lies on segment ac, then there can be only one solution

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brainly.com/question/2437195

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7 0
2 years ago
A hemispherical tank is filled with water and has a diameter of 22 feet. If water
taurus [48]

Given :-

Diameter of tank = 20 feet

Radius of tank, r = 20/2 = 10 feet

To Find :-

Volume of the hemisphere

Formula to be used :-

Volume of the hemisphere = 2/3 × π × r³

Solution :-

Putting the values, we get

Volume of the hemisphere = 2/3 × π × r³

⇒ Volume of the hemisphere = 2/3 × 22/7 × 10 × 10 × 10

⇒ Volume of the hemisphere = 44000/21

⇒ Volume of the hemisphere = 2095. 23 feet³

Now, Total weight of the water

⇒ Total weight of the water = 62.4 × 2095.23

⇒ Total weight of the water = 130742.35 pounds

Hence, the Total weight of the water is 130742.35 pounds

Step-by-step explanation:

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3 years ago
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3 years ago
(-4)-(-2)-{(-5)-[(-7)+(-3)-(-8)]}
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Answer:

is one

Step-by-step explanation:

its just one i know trust me

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