Rearrange the 2nd equation
-36a-24b-16c
divide the whole thing by 4 and you'll get
-9a-6b-4c
you'll realize it looks the same as your first equation except that all the + has become minus so the answer will be -7 instead for your new equation
-9a-6b-4c=-7
multiply the whole thing by 4 and you'll get
-36a-24b-16c = -28
so the answer you want is -28
Answer:
8 1/2
Step-by-step explanation:
They are on opiate sids of zero so add the absolute values together to get 1/2
Answer:
256 quarts remain.
Step-by-step explanation:
.8x320=256
17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i
19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i
hope this helps, God bless!
Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
