Answer:
(3x+4)(3x+2)
Step-by-step explanation:
Given: <span>9=(1/27)^(a+3)
[Note: Please review rules of PEMDAS.
The question posted as is means
</span><span>9=[(1/27)^a]+3 which is probably not what you mean. It has been interpreted with (a+3) as the exponent, please check.]
</span><span>
Need to find value of a that satisfies above.
We will first isolate a in order to solve for its value.
</span>9=(1/27)^(a+3)
Switch unknown to the left
(1/27)^(a+3) = 9
Since both 27 and 9 are powers of 3, we can take log to base 3.
take log (base 3) on both sides, applying rule of logarithm of exponents.
(a+3)log_3(1/27)=log_3(9)
(a+3)log_3(3^(-3))=log_3(3^2)
Apply definition of logarithm [log_a(a^k)=k]
(a+3)(-3)=2
(a+3)=-2/3
a=-3 2/3=-11/3
Check: (1/27)^(-11/3+3)=(1/27)^(-2/3)=(3^(-3))^(-2/3)=3^(-3(-2/3))=3^2=9 ok
Answer: a=-11/3 or a=-3.667 (approx.)
Answer:
2
Step-by-step explanation:
she will have 2 arangments of one rose and two daisies.
k=2(11-k)+14
k=22-2k+14
2k+k=22+14
3k=36
k=36/3
k=12<em></em>
Answer:
Please find the solution in the image attached below.
Step-by-step explanation:
Tcos60 -2T sin(90-theta) = 0
Tcos60 = 2T(cos theta)
cos 60 = 2cos theta
cos60 = 2cos theta
1/4 = cos theta
theta = 75.5
So the angle to the vertical = 90-75.5 = 14.5
S
Resolving perpendicular
Tsin60 + 2Tsin75.5 - 2g = 0
T(sin 60 + 2sin75.5) = 2g
T = 19.6/sin 60 + 2sin75.5
T = 19.6/1.936 + 0.866
T = 19.6/2.802 = 7.0N
Hope this helps!
