Answer:
The Skater's final angular speed =8rad/s
Explanation:
Let initial momentum of inertia be I1
Let final momentum of inertia be I2
But I2= I1/2
It is decreased by one-half
There is no external torque on the system, therefore
I1w1=I2w2
I1×4=(I1/2)×w2
Dividing through by I1 on both sides leaves you with:
4=w2/2
Cross multiply
W2=4×2=8rad/s
Answer:
<em>| Fn | = 258 N</em>
Explanation:
<u>Net Force</u>
The net force vector is the sum of all the force vectors applied to a body.
There are four forces applied to a car:
325N to the north
175N to the south
465N to the east
255N to the west
To simplify the calculations, we find the net force by each axis separately, considering forces to the right and upward as positive.
Fx = 465 N - 255 N = 210 N
Fy = 325 N - 175 N = 150 N
The magnitude of the net force is:



| Fn | = 258 N
Answer:
Final speed of the ball = Vf= 12.52 m/s when it hits the ground
Explanation:
Height = S= 8.0 m
Initial Velocity= Vi = 0 m/s
Final Velocity= Vf =?
Acceleration due to gravity= a=9.8m/s²
Using Newtons third equation of motion
2as= Vf²- Vi²
2(9.8) 8= Vf²- 0
156.8= Vf²
Vf=√156.8= 12.52m/s
Final Speed of the ball is 12.52 m/s