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matrenka [14]
3 years ago
15

student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir

onment, how much height will it lift a 1.5 kg mass?
Physics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

Q_1 = W + Q_2

here we know that

Q_1 = 300 J

Q_2 = 50 J

now we have

W = 300 - 50

W = 250 J

so work done by the engine is 250 J

now we have

W = mgh

250 = 1.5 \times 9.81 \times h

h = 17 m

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A cavity that has a hole in it......it's the best example of black body radiators....
8 0
3 years ago
A length change 0.08 m will occur for an object that is L= 56 m long. If the coefficient of thermal expansion is5.3 x 10 /C and
ArbitrLikvidat [17]

Answer:

Increase in temperature =  269.54 °C

Explanation:

We have equation for thermal expansion

          ΔL = LαΔT

Change in length, ΔL = 0.08 m

Length, L = 56 m

Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1

Change in temperature, ΔT = T - 253

Substituting

          0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)

         (T - 253) = 269.54

           T = 522.54 °C

Increase in temperature =  269.54 °C      

4 0
3 years ago
An experiment is designed to see if sleep affects the number of vocabulary words subjects can remember. The dependent variable i
Kaylis [27]

The dependent variable is: <em>"number of vocabulary words subjects can remember"</em>

<h3>Which is the dependent variable?</h3>

In an experiment, we basically see how changing one variable affects another variable.

In this case, the experiment is:

<em>" if sleep affects the number of vocabulary words subjects can remember."</em>

Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).

So the correct answer is:

<em>"number of vocabulary words subjects can remember"</em>

If you want to learn more about variables:

brainly.com/question/15246027

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7 0
2 years ago
What is (a) the wavenumber and (b) the wavelength of the radiation used by an fm radio transmitter broadcasting at 92. 0 mhz?
yulyashka [42]

The wavenumber and (b) the wavelength of the radiation used by an fm radio transmitter broadcasting at 92. 0 mhz will be  31.25 * 10^{2} m^{-1} and 0.032 * 10^{2} m respectively

Forms of electromagnetic radiation like radio waves, light waves or infrared (heat) waves make characteristic patterns as they travel through space. Each wave has a certain shape and length. The distance between peaks (high points) is called wavelength.

Wavenumber, also called wave number, a unit of frequency, often used in atomic, molecular, and nuclear spectroscopy, equal to the true frequency divided by the speed of the wave and thus equal to the number of waves in a unit distance.

wavelength = ?

frequency = 92 m Hz = 92 * 10^{6} Hz

speed of light = 3 * 10^{8} m/s

speed of light = frequency * wavelength

wavelength = speed of light  / frequency

                     = 3 * 10^{8}  / 92 * 10^{6}

                     = 0.032 * 10^{2} m

wavenumber = 1 / wavelength

                      = 1 / 0.032 * 10^{2} m

                      = 31.25 * 10^{2} m^{-1}

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5 0
1 year ago
The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t
Oksanka [162]

The acceleration due to gravity of Mars is 3.5\ m / s^{2}

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

      \text {Gravitational force of planet}=\frac{G M m}{R^{2}}

Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

   Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}

  Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}

  \text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}

 \text { Acceleration }=3.5\ \mathrm{m} / \mathrm{s}^{2}

3 0
3 years ago
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