The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
Answer:
The center is at (3, -4), and the radius is 9.
Step-by-step explanation:
x² + y² − 6x = 56 − 8y
Move x and y terms to one side.
x² − 6x + y² + 8y = 56
Complete the squares.
x² − 6x + 9 + y² + 8y + 16 = 56 + 9 + 16
(x − 3)² + (y + 4)² = 81
The center is at (3, -4), and the radius is 9.
Answer:
The equation that represents the total distance travelled by numbers of times he goes to work by Michael is y = 4*x
Step-by-step explanation:
Since Michael has to travel 4 km each time he goes to work if he goes to work 2 times he'll have to travel 8 km, if he goes 3 times he'll have to travel 12 km. If we keep doing this we'll realize that the distance travelled by Michael is given by the number of times he goes to work multiplied by 4. The equation that represents that is:
y = 4*x
The domain is the set of all the values of X therefore it would be D.
