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pickupchik [31]
3 years ago
14

What is the average rate of change from x = -3 to x = 3

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0
I believe it is -1 since -3 times -1 equals 3 and the rate of change is based on the slope of a line 
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Please Help What is the value of the expression? −34+(1/10÷2/5)
sweet-ann [11.9K]
Regarding your (1/10 divided by 2/5):  I'm going to regard this as

(1/10) divided by (2/5).  

First, write 

 1
---         
10

Invert the fraction 2/5 and then multiply 1/10 by 5/2:

1(5)
-------- = 1/4, after reducing  5/10.
10(2)

Thus, <span>−34+(1/10÷2/5) yields -34 + 1/4, or   -33 3/4.</span>
5 0
3 years ago
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Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
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Paraphin [41]
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3 years ago
X + y = 4<br> 2x - 5y = 15<br> Graphing
sesenic [268]

Answer:

Step-by-step explanation:

5x + 5y = 20

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5 + y = 4

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(5, -1)

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Fred ran 4 miles in 30 minutes. Janet ran 6 miles in 40 minutes. Fred and Janet each continue running at their same rate for 1 h
borishaifa [10]
Fred: 4m: 30 minutes=8 miles per hour
janet: 6m: 40minutes= 3 miles every 20 minutes=9 miles per hour
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filled in:

 Fred ran 4 miles in 30 minutes. Janet ran 6 miles in 40 minutes. Fred and Janet each continue running at their same rate for 1 hour. fred will run 8 miles in 1 hour. Janet will run 9 miles in 1 hour. Janet will run 1 miles farther in 1 hour

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