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ahrayia [7]
3 years ago
15

Mike is going to put his $97 in a savings account. This account earns 4% simple interest. Find the INTEREST EARNED after 5 years

.
Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0

$19.4

Step-by-step explanation:

Simple Interest=SI

Principle(deposit)=P(97)

Rate= R(4/100=0.04)

Time= T(5)

SI=P•R•T

SI=97x0.04x5

SI=19.4

Interest earned = $19.4

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Ludovica creates flashcards for her vocabulary words. She creates 3 more cards per verb than per noun. Ludovica creates 2 fewer
S_A_V [24]

Answer:

5 per noun, 8 per verb

Step-by-step explanation:

start by defining what each variable is

v = n+3

v = 2n-2

substitute v for one of the equations above

n+3 = 2n-2

subtract n from both sides

3 = n-2

add 2 to each side

5 = n

so there are 5 flashcards per noun

substitute 5 in for n in both equations

v = 5+3

and

v = 2(5)-2

solve both equations

v = 8 and v = 8

so there are 8 flashcards per verb

5 0
4 years ago
Write an equation of a line in Slope-Intercept Form that passes through the points (3, -2) and (1, 4)
mihalych1998 [28]
The correct answer is

7 0
4 years ago
JK and LM are straight lines. Find /NOK.<br> ( help me pls)<br>​
VashaNatasha [74]

Answer:

NOK = 58

Step-by-step explanation:

Given

JOM = 108

LON = 50

Required

Find NOK

From the attached triangle, we have:

LOK = JOM =108 --- Corresponding angles

And

LOK = LON + NOK

Substitute for LOK and LON

108= 50+ NOK

Make NOK the subject

NOK = 108 - 50

NOK = 58

8 0
3 years ago
What is the value of the expression shown below 10+(2x3)^2 divided by 4x (1/2)^3
stira [4]

Answer:

10 + (2 x 3)^2 / 4 x (1/2) ^3

First do the parentheses

2 x 3 = 6

1 / 2 = 0.5

We are left with

10 + 6^2 /4 x 0.5^3

Do exponents

6 x 6 = 36

0.5 x 0.5 x 0.5 = 0.125

10 + 36 / 4 x 0.125

Divide by 4 and multiply by 0.125

36 / 4 = 9

9 x 0.125 = 1.125

We are left with

10 + 1.125 = 11.125

The answer is 11.125

Step-by-step explanation:

7 0
3 years ago
A 2600-pound truck is stopped at a red light on a hill with an incline of 25°. Ignoring the force of friction, what force is req
Verizon [17]

Answer:

  about 1099 pounds

Step-by-step explanation:

The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill. The question is asking about this latter force.

The magnitude of the force parallel to the hillside required to keep the truck stationary is ...

  (2600 lb)·sin(25°) ≈ 1098.81 lb ≈ 1099 lb

8 0
3 years ago
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