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4 years ago

How can u turn a liquid to a solid

Mathematics

2 answers:

Naya [18.7K]4 years ago

7 0

Freeze it

Hope this helped :)

Allushta [10]4 years ago

5 0

Freeze it. How do you turn water into ice? You freeze it. :)

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A) The sum of −3x+5 and 7−4x is subtracted from 5x+17.

AlekseyPX

A. -3x+5+7-4x
-3x-4x+5+7
-7x+12

-7x+12-5x+17
-7x-5x+12+17
-12x+29

B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
-11x-11

8 0

3 years ago

The answer of this question

dolphi86 [110]

Answer:

i think it is c

Step-by-step explanation:

not 100% sure tho

4 0

4 years ago

An isosceles triangle has a base 9.2 units long. If the congruent side lengths have measures to the first decimal place, what is

Nadusha1986 [10]

Question:

An isosceles triangle has a base of 9.6 units long. If the congruent side lengths have measures to the first decimal place, what is the possible length of the sides? 9.7, 4.9, or 4.7

Answer:

4.9 is the shortest possible length of the sides.

Step-by-step explanation:

Given:

The base of the triangle base = 9.2 units

To Find:

The shortest possible length of the sides = ?

Solution:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

So According to the theorem

$x+x > 9.6$

$2x > 9.6$

$x > \frac{9.6}{2}$

$x > 4.8$

In the given option 4.9 is the shortest length greater than 4.8 that can be possible.

3 0

4 years ago

Point A (-3, 5) is translated 4 units right and 2 units down. What are the coordinates of A'?

mixas84 [53]

Answer:

(1,3)

Step-by-step explanation:

it moved in the positive X axis (right), and the negative Y axis (down)

5 0

4 years ago

Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

8 0

4 years ago