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3 years ago

Please help! If i don't get all my homework done I can't leave the house, but I'm stuck on this question.

Mathematics

1 answer:

TEA [102]3 years ago

7 0

Plug y=-4x+5 into a website called desmos, it will give you a graph! The y-intercept is 5 and it’s at a slope of 4/1

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What is the remainder of (3x^4+2x^3-x^2+2x-14)/ (x+2)

Allisa [31]

Hi,

I assume the forward slash meant it as a fraction VS it being a division symbol. To answer your question, the remainder is 10.

Hope this helps.

4 0

3 years ago

sandra used 2 jars of beads to make 16 necklaces how many jars of beads would she need to make 192 neclaces

garik1379 [7]

Answer:

24 Jars

Step-by-step explanation:

Do 16/2, which gives you eight for every necklace. Then do 192/8 which would give you 24. So, she would need 24 jars for 192 necklaces.

4 0

2 years ago

Read 2 more answers

Plzz help

ratelena [41]

Answer:

Step-by-step explanation:

Ok so the starting ratio is 4:6

It is 20 members last year and 25 member the next year.

LAST: 20 THIS YEAR:25

When u use the ratio of 4:6 IN 25 students, u get

8:12 LAST year.

You can check because 8 + 12 = 20, or the total number of students.

5 0

3 years ago

Read 2 more answers

A company services home air conditioners. It is known that times for service calls follow a normal distribution with a mean of 7

SCORPION-xisa [38]

Answer:

The probability that exactly eight of them take more than 93.6 minutes is 5.6015 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that it is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes.

A random sample of twelve service calls is taken.

So, firstly we will find the probability that service calls take more than 93.6 minutes.

Let X = times for service calls.

So, X ~ Normal( $\mu=75,\sigma^{2} =15^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 75 minutes

$\sigma$ = standard deviation = 15 minutes

Now, the probability that service calls take more than 93.6 minutes is given by = P(X > 93.6 minutes)

P(X > 93.6 min) = P( $\frac{X-\mu}{\sigma}$ > $\frac{93.6-75}{15}$ ) = P(Z > 1.24) = 1 - P(Z $\leq$ 1.24)

= 1 - 0.8925 = 0.1075

The above probability is calculated by looking at the value of x = 1.24 in the z table which has an area of 0.8925.

Now, we will use the binomial distribution to find the probability that exactly eight of them take more than 93.6 minutes, that is;

$P(Y = y) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; y = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 12 service calls

r = number of success = exactly 8

p = probability of success which in our question is probability that

it takes more than 93.6 minutes, i.e. p = 0.1075.

Let Y = Number of service calls which takes more than 93.6 minutes

So, Y ~ Binom(n = 12, p = 0.1075)

Now, the probability that exactly eight of them take more than 93.6 minutes is given by = P(Y = 8)

P(Y = 8) = $\binom{12}{8}\times 0.1075^{8} \times (1-0.1075)^{12-8}$

= $495 \times 0.1075^{8} \times 0.8925^{4}$

= 5.6015 $\times 10^{-6}$ .

6 0

3 years ago

How do you answer this

makkiz [27]

The bottom row is 15/30 3/6 9/18 10/20

5 0

3 years ago