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Lapatulllka [165]
3 years ago
9

The shortest side of a right triangle measures 13 m. the lengths of the other two sides are consecutive integers. Find the lengt

hs of the other two sides.

Mathematics
1 answer:
mariarad [96]3 years ago
6 0
So, the shortest side is 13, the other two fellows are two consecutive values.... ok... let's say the other leg is "a", a consecutive value to that will be a+1, so the hypotenuse is "a + 1" then

check the picture below

and surely you'd know what "a" is

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klemol [59]
A is correct. Hope my answer helped u :)
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2 years ago
In a 30° -60° -90° triangle, what is the length of the hypotenuse when the shorter leg is 8 m? Enter your answer in the box.
yan [13]

Answer:

16

Step-by-step explanation:

In a 30 60 90 degree triangle, the hypotenuse is always double the shorter leg. Hope this helps! :)

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2 years ago
Evaluate 3C1.<br><br> a)3<br> b)1<br> c)2<br> d)6
murzikaleks [220]

Answer: Option a) 3

Step-by-step explanation:

The formula for calculating combinations is as follows

nCr = \frac{n!}{r!(n-r)!}

Where "n" is the amount of items in a set and you can choose "r" from them

3C1 reads as: The combination of 1 in 3. You have a set of 3 elements and choose 1 of them.

n = 3\\\\r = 1

So :

3C1=\frac{3!}{1!(3-1)!}\\\\3C1=\frac{3!}{1!*2!}\\\\3C1=\frac{3*2*1}{1*2*1}\\\\3C1=3

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2 years ago
I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!
Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

p + j = 79

1.65p + 1.36j = 118.17

(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

3 0
3 years ago
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