All categories

3 years ago

What numbers of vegetables v can he buy and stay under his spending limit?

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

Answer:

$37 + ($0.75/veg.)v <$ 50

Step-by-step explanation:

Let v be the number of vegetables at $0.75/vegetable.

$37 + ($0.75/veg.)v <$ 50

You might be interested in

Which of the following does not belong with the other three? Explain your reasoning

Savatey [412]

???????????I don't know exactly what you mean

6 0

3 years ago

What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po

emmasim [6.3K]

$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA$
$\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA$

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
$\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j$

The cross product is

$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

So, the flux is given by

$\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA$
$\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du$
$\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv$
$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

where $t=-\sin v$ in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

$\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi$

5 0

3 years ago

HELP FAST YOU CAN HAVE ALL MY POINTS

DiKsa [7]

The answer might be Y=1/4x+2

6 0

3 years ago

How do you make all of these equation true in the circles you put either addition sign division sign multiplication sign subtrac

love history [14]

Answer:

in steps

Step-by-step explanation:

12 - 6 x 2 + 3 = 3

(12 - 6 ÷ 2) x 3 = 27 .... ??

12 ÷ 6 + 2 x 3 = 8

12 ÷ 6 + 2 + 3 = 7

12 + 6 ÷ 2 + 3 = 18

4 0

3 years ago

Which of the following options results in a graph that shows exponential growth. F(x) = 0.4(3)^x. F(x) = 3(0.5)^x. F(x) = 0.8(0.

Andre45 [30]

$f(x)=a^x\\\\if\ a \ \textgreater \ 1\ then\ a\ function\ is\ an\ exponential\ growth\ function$

$f(x)=0.4(3)^x\to a=3 > 1\ OK!\\f(x)=3(0.5)^x\to a=0.5 < 1 :(\\f(x)=0.8(0.9)^x\to a=0.9 < 1 :(\\f(x)=0.9(5)^{-x}=0.9\left(\dfrac{1}{5}\right)^x\to a=\dfrac{1}{5} < 1\ :($

Answer: $f(x)=0.4(3)^x$

5 0

3 years ago