The values of b and c are -4 and 4 respectively
<h3>How to determine the values of b and c?</h3>
The function is given as:
f(x) = x^2 + bx + c
Differentiate f(x)
f'(x) = 2x + b
Set to 0
2x + b = 0
Solve for b
b = -2x
The minimum is (2, 0).
So, we have:
b = -2 * 2
b = -4
Substitute b = -4 in f(x) = x^2 + bx + c
f(x) = x^2 - 4x + c
Substitute (2, 0)
0 = (2)^2 - 4(2) + c
This gives
0 = 4 - 8 + c
Evaluate
c = 4
Hence, the values of b and c are -4 and 4 respectively
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Answer:
No Solution
Step-by-step explanation:
Let us see the various conditions to check the number of solutions for a pair of linear equations.
Let our linear equations are
ax+by=c
px+qy=r
i) for Unique Solution
≠ 
= 
≠ ≠
ii) For No Solution
= ≠
iii) For many Solutions
≠ =
Let us see what ratio we have for our linear equation s
here
a=1 , b=-2 , c= 4
p=-3 , q = 6 , r = 12
= 
= - 
= 
= -
= 
=
- = - ≠
Hence it satisfies the second condition of No solution
1258 centimeters is equal to 12.58 meters :)
The correct answer is 105.8
Answer:
20w+8
Step-by-step explanation:
hope it helps..................
