Answer:
2 quarters and 15 dimes
Step-by-step explanation:
15 dimes = $1.50
2 quarters = $0.50
$1.50+$0.50=$2.00
Be more specific. Like what is it asking you to do ? I'm trying to help. :)
Answer:
The first one
Step-by-step explanation:
Answer:
no, there is an infatuate amount of solutions
Step-by-step explanation:
1.2(2x-5)=2/5(2x-15)+1.6x
2.4x -6 = .8x -6 +1.6
2.4 -6 = 2.4-6
0=0 ( infatuate)
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
