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Katena32 [7]
3 years ago
12

a pitcher throws a .015 kg baseball from rest to a final velocity of 45. what is the magnitude of the change in momentum of the

baseball
Physics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

0.675 kg m/s

Explanation:

Momentum = mass x velocity

= 0.015 x 45 = 0.675 kg m/s

P.S. I'm not sure of this answer,  so it might be a good idea to check this with some other sources.

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