To calculate the strength of the eye lens, we use the formula
( thin lens formula)
Here, u is the object distance and v is image distance.
Given, and
Therefore,
Thus, strength of the eye lens is
The unit of measurement for mass & weight is kilograms (kg)
Answer:
d. the same within the uncertainty of each measurement method
Explanation:
The density of an object and in general any physical property, has the same value regardless of the method used to measure it, either directly or indirectly. Since two completely different valid methods are used, the results must be the same, taking into account the level of precision of each of the methods.
Answer:
only E is true
Explanation:
A) to find out if it would fall 4x as fast by 2x the time we can look at the formula for free fall:
for free fall the Y = g where Y is the distance fallen, g is gravity and t is time
so since the rate at which an object falls is the same (gravity stays the same) it will not fall faster with any alteration
B) An object would fall half the distance if you double the time
here we may need to check with an example:
lets say we fall for 2 seconds in the first and 4 in the second:
Y= 1/2 (9.8) (2)^2 gives 19.6m fallen
Y= 1/2 (9.8) (4)^2 gives 78.4m fallen
from this we can see that doubling the time does not half the distance
C) all objects fall at the same rate no matter their mass so this statement is false
D) from the example above we see again that doubling time does not double the distance
E) this statement is true
Answer:
The balanced equations are as follows:
✅ FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl
✅ CH₄ + O₂ ➡ CO₂ + 2H₂O
✅ 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂
✅ PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄
Explanation:
In the equation, FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl, Charlie will adjust the number of atoms in NH₄OH in order for NH₄, Cl and OH to balance in the product side. 3 was placed in front of NH₄OH and NH₄Cl in order the balance it.
In the equation, CH₄ + O₂ ➡ CO₂ + 2H₂O, Charlie will adjust the number of atoms in H₂O. 2 was placed in front of H₂O in order to balance the atoms in the reactant and product sides.
In the equation, 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂, Charlie will adjust the number of atoms in the reactant side in order for the product side to be balanced.
In the equation, PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄, Charlie will adjust the number of atoms in H₂O and HCl for the equation to be balanced. 4 and 5 were placed in front of H₂O and HCl respectively in order for the equation to be balanced.
In chemical equations, it is required that the number of atoms of each element found in the reactants must be equal to the number of atoms of each element found in the products. This makes the chemical equation balanced.