An atom is the smallest part of an element
Answer:
tectonic plates move in opposite direction
Tectonic plates are not necessarily moving in opposite directions, but if there directions are different they form plate boundaries. If they were moving in the same direction they would become the same plate. The more opposite the direction, the more obvious the fault.
Examples of plate boundaries:
Divergent: moving away from each other - mid-Atlantic ridge
Convergent: moving towards each other - the Himalayas (Indian plate subducting under the Eurasian plate forcing up the mountains)
Transform: sliding laterally along each other - San Andreas fault
Answer:
(a) Number of electrons per second strike the target is 3.125 x 10¹⁵.
(b) Charge that strikes the target in 0.750 s is 3.75 x 10⁻⁴ C .
Explanation:
(a) Let n be the number of electrons per second strike the target. We know that current (I) is given by the relation :
I = n x e
Here e is charge of electron.
Substitute 0.500 x 10⁻³ A for I and 1.6 x 10⁻¹⁹ C for e in the above equation.
0.500 x 10⁻³ = n x 1.6 x 10⁻¹⁹
n = 3.125 x 10¹⁵
(b) Let q be the charge that strikes the target. We know that :
q = I x t
Here I is current and t is time.
Substitute 0.500 x 10⁻³ A for I and 0.750 s for t in the above equation,
q = 0.500 x 10⁻³ x 0.750
q = 3.75 x 10⁻⁴ C
Answer:
The answer is 3.33m
Explanation:
The acceleration "a" is constant.
Acceleration is the variation of velocity over time,
.
solving the last equation
,
where 
because the airplane starts from rest.
Once again, velocity is the variation of distance over time.
then
where 
if we consider the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).
If 
at 
, then
and the final expression for the distance is
.
If t = 2s, x = 4.44 m. Which means thad the additional distance is
Answer:
24.3 degrees
Explanation:
A car traveling in circular motion at linear speed v = 12.8 m/s around a circle of radius r = 37 m is subjected to a centripetal acceleration:
Let α be the banked angle, as α > 0, the outward centripetal acceleration vector is split into 2 components, 1 parallel and the other perpendicular to the road. The one that is parallel has a magnitude of 4.43cosα and is the one that would make the car slip.
Similarly, gravitational acceleration g is split into 2 component, one parallel and the other perpendicular to the road surface. The one that is parallel has a magnitude of gsinα and is the one that keeps the car from slipping outward.
So 
