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Artemon [7]
3 years ago
7

Which of the following statements it's true about Sir isaac Newton

Physics
2 answers:
timama [110]3 years ago
7 0

Answer

C. He made a connection between the mass of an object and the distance between them

krek1111 [17]3 years ago
5 0
The legend is that he discovered gravity when an apple feel on his head. I don’t know what the true story is, but that’s what I’ve heard so maybe A??
Although, I’m pretty sure it could also be C
So... between A and C, however, I don’t want you to get it wrong so I would recommend getting another opinion
Hope this helps!
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Please help! I’ll give Brainliest
babymother [125]

Answer:

9.8 secs

Explanation:

the ball is in the air so it takes 9.8 secs to get to the ground

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A combination reaction is when two or more _____ combine to form one product. A decomposition reaction is when a substance break
Leya [2.2K]

Answer:

elements

Explanation:

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Three people pull simultaneously on a stubborn donkey. jack pulls eastward with a force of 92.5 n, jill pulls with 89.9 n in the
alekssr [168]
Jack------------ force of 92.5 n   eastward-------Fjack(X)=92.5 n   Fjack(Y)=0

<span>jill ------------------------------- force of 89.9 n   northeast
Fjill(X)=cos45*89.9=63.57 n
</span>Fjill(Y)=sin45*89.9=63.57 n<span>

</span>jane -----------------------------force of 163 n   southeast
Fjane(X)=cos45*163=115.26 n
Fjane(X)=-sin45*163=-115.26 n

Ftotal (X)=92.5+63.57+115.26=271.33 n
Ftotal (Y)=0+63.57-115.26=-51.69 n

Fotal=((271.33)^2+(-115.26)^2) ^0.5=294.80 n southeast

the magnitude of the net force the people exert on the donkey. is 294.80 n southeast
7 0
3 years ago
Initially (at time t = 0) a particle is moving vertically at 7.5 m/s and horizontally at 0 m/s. Its horizontal acceleration is 1
Lelu [443]

Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

initial horizontal velocity = 0 m/s

angle = 49◦

using kinetic equation

final velocity in vertical direction

v sinθ    = u_y   - gt ........................(1)

final velocity in horizontal direction

v cosθ = u_x   + a_x × t

here   u_x = 0.0 m/s

v cosθ = a_x×t ......................(2)

Dividing equation (1) / (2)

tan \theta =\dfrac{u_y - gt}{a_x\times t}

solving for time t

t = \dfrac{u_y}{tan \theta \times a_x + g}

u_y   =   initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity   = 9.8 m/s²

θ = 43° ,   u_y   =  7.5 m/s    

t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}

t = 0.657 s

time taken by the particle is t = 0.657 s

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3 years ago
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Vlad1618 [11]

Answer:

I think its the 2nt

Explanation:

PLZ MARK AS BRAINLEST!!!

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