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3 years ago

I have missing work for some reason I just can’t seem to pay attention

Mathematics

2 answers:

hichkok12 [17]3 years ago

8 0

Answer:

What grade are you in? You aren't supposed to do all your missing work in one day try to get onto your work currently if you have extra time do your missing work. Remember you wanna do good on it you don't wanna finish all and be stressed out because you'll have even more missing work. If you do it just to finish it won't help either. Be focused while doing it but also be free and don't bother yourself. Such as if you played valorant for 5 hours do a missing assignment then keep on playing (that is if you already finished what you did)

Step-by-step explanation:

pychu [463]3 years ago

7 0

Answer:

lol same

Step-by-step explanation:

idek

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One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago

Look at the relation below.

Mariana [72]

Answer:

If we remove one ordered pair (1, -2) then the set of points would represent a function.

Hence, option C i.e. (1, -2) is correct.

Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

Given the relation

{(-2,4), (4,-2), (1,1), (1,-2), (0,1), (6,4)}

If we closely check, we can observe that the input x = 1 is repeated twice.

In other words, there are two ordered pairs (1, 1) and (1, -2) with the same input x = 1. So, x = 1 is duplicated here.

We know that we can not have duplicated inputs as there should be only 1 output for each input.

Therefore, if we remove one ordered pair (1, -2) then the set of points would represent a function.

Hence, option C i.e. (1, -2) is correct.

3 0

3 years ago

Whats the Answer? I need help and quick

polet [3.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The Coffee Shop around the Corner (CS) is famous for its fresh-made muffins. Hank, the owner of CS, knows that the demand for mu

Anastasy [175]

Answer:

The responses to the given question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

$Day \ \ \ \ \ \ \ \ \ \ Period \ \ \ \ \ \ \ \ \ \ Demand \ \ \ \ \ \ \ \ \ \ 5-period moving average$

$1 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 37 \\\\$

$Afternoon \ \ \ \ \ \ \ \ \ \ \ 25 \\\\ Evening \ \ \ \ \ \ \ \ \ \ \ 9$

$2 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \48 \\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ 28 \\\\$

$Evening \ \ \ \ \ \ \ \ \ \ \ 14 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.4 \\\\$

$3 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 53 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24.8\\\\$

$Afternoon \ \ \ \ \ \ \ \ \ \ \ 33 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30.4\\\\Evening \ \ \ \ \ \ \ \ \ \ \ 17 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35.2\\\\$

$4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29\\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.25\\\\Evening \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34.33333\\\\$

6 0

3 years ago

What is the coefficient of x2 in the expansion of (x + 2)3?

Vinvika [58]

I think 6 is the answer. Hopefully I answered your question

4 0

3 years ago