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SSSSS [86.1K]
3 years ago
15

Simple machines make work easier. You must lift and move this load of soil for your parents. It is heavy! You are using two simp

le machines when you use this wheelbarrow. What simple machine included in the wheelbarrow makes it easier to move the soil from one place to another?
A) The wheel and axle
B) The bucket (fulcrum)
C) A lever (handles and bucket)
D) An inclined plane (fork holding wheel)
Chemistry
1 answer:
nevsk [136]3 years ago
6 0
The answer is letter D
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A student balanced the chemical equation Mg + O2 →MgO by writing Mg + O2 → MgO2. Was the equation balanced correctly? Explain yo
Amanda [17]

Explanation:

Charges on both magnesium and oxygen is 2. Though opposite in sign, they have equal charges so, both of them will be cancelled by each other.

As a result, formula of magnesium oxide is MgO and not MgO_{2}.

The student write the equation as Mg + O_2 \rightarrow MgO_2, it is not correct.

Therefore, given equation will be balanced as follows.

          2Mg + O_{2} \rightarrow 2MgO

Since, number of atoms on both reactant and product side are equal. Hence, this equation is completely balanced.

7 0
3 years ago
Sandy puts a paper clip on the table. Then, she puts a magnet near the paperclip. The paperclip begins to move.
Akimi4 [234]
Applied forces/or unbalanced:i hope that helps you
3 0
3 years ago
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What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?
Phantasy [73]

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

8 0
3 years ago
In an extraction procedure, it is advisable to: save all layers until the experiment is complete. throw away all layers as soon
LenKa [72]

All the layers should be kept until the experiment is complete.

<h3>What is extraction?</h3>

In chemistry, solvent extraction is accomplished by adding a sample containing the substance to be separated into a system of two solvents, an aqueous layer and an organic layer.

It is important to note that all the layers should be kept until the experiment is complete. No layer ought to be discarded before the work is completed.

Learn more about solvent extraction:brainly.com/question/11041092

4 0
2 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas
Gwar [14]

The equation structure for the above mentioned reaction can be written as  

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

Thus a Balanced equation of the above mentioned reaction is written.

8 0
3 years ago
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