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4 years ago

Nitric oxide can be oxidized in air to form nitrogen dioxide. At normal atmospheric concentrations this is a very slow process.

Chemistry

1 answer:

lawyer [7]4 years ago

6 0

Answer:

exothermic

Explanation:

This is an exothermic reaction because you can see the 232.4 kJ at the end of the reaction. That means that 232.4 kilo-joules are released when the reaction happens; when energy is released during a reaction, the reaction is exothermic.

Tell me if you need anything else! :)

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The brown summer feathers of ptarmigans, small Arctic birds, are replaced by white feathers after winter arrives. Which statemen

ivolga24 [154]

D because animals changing colors is a mutation

8 0

3 years ago

Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

Answer: The value of equilibrium constant for the reaction is 2448.1

Explanation:

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0

4 years ago

How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M? 205 grams 0.205 grams 3.5

Firlakuza [10]

A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.

3 0

3 years ago

Read 2 more answers

I need all the answers ASAP

Bezzdna [24]

Answer:

explanation

Explanation:

Magnesium-

a. Solid

b. Metal

c. Natural

d. Mg

e. Alkaline earth metals

Ill answer the rest if you can mark brainliest

7 0

2 years ago

If the temperature of a reversible reaction in dynamic equilibrium decreases, how will the equilibrium change?

myrzilka [38]

Answer:

D. It will shift towards the exothermic reaction.

Explanation:

4 0

3 years ago