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elixir [45]
3 years ago
12

What are the solutions to the quadratic equation 4x2 + 28x = 0?

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

x = {-7, 0}

Step-by-step explanation:

4x^2 + 28x = 0

Divide both sides by 4

x^2 + 7x = 0

Factor out x

x(x + 7) = 0

---------------------------

From the zero product rule

x = 0

and

x + 7 = 0

subtract 7 from both sides

x = -7

x = {-7, 0}

AleksandrR [38]3 years ago
6 0

Answer:

x is 0 or -7

Step-by-step explanation:

4x^{2} +28x=0\\4x(x} +7)=0\\4x=0 x=0\\x+7=0\\x=-7

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Answer:

<h2>LA = 24 ft²</h2>

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

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4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2

The Lateral Area:

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8 0
3 years ago
(3 pt) point v is graphed on a number line at –6. point u is 8 units away from point v on the number line. what could be the coo
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