Answer:
The correct option is D
D) The graph of function f(x) is shifted right 3 units and up 4 units
Step-by-step explanation:
Lets the function be y = f(x)
To shift the graph 3 units to the right, we add -3 to the x term of the function:
Function becomes y' = f(x-3)
Then to shift the graph up by 4 units, we add -4 to the y term of the function:
Function becomes:
y - 4 = f(x-3)
y = f(x-3) +4
g(x) = f(x-3) +4
Hence the correct option is D, as the graph is shifted to the right by 3 units and also shifted up by 4 units
Answer:
-1<X<2
Step-by-step explanation:
i think this is correct
Its answer 3 because they are the only difference with two squared numbers
Answer:
Step-by-step explanation:
Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)
