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Sophie [7]
3 years ago
6

For x=4 simplify 2x+(6-3)2 I need help

Mathematics
1 answer:
shusha [124]3 years ago
8 0

Answer:

Step-by-step explanation:

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PLEASE HELPP PRE CAL<br><br> What is the greatest common factor of 8m^2, 4m, and 10m^4
luda_lava [24]

Answer:

2m

Step-by-step explanation:

For m, I look for the greatest power of m that is in all of the expressions. Since the first has m^2, the second has m, and the third has m^4, the greatest power of m that is in all expressions is m.

For the number, I look for the greatest factor of 8, 4, and 10. A trick would be to look at the smallest number since the greatest common factor can only be less than or equal to the smallest number. So looking at 4, the factors are 1,2,4. 4 is not a common factor since it does not divide into 10, but 2 is so 2 is the greatest common numerical factor.

Combine 2 and m to get 2m.

4 0
3 years ago
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Which expression could represent the real-world situation below?
shtirl [24]

Answer:

Option A is your answer ☺️☺️

4 0
2 years ago
Find the inverse of the given function.<br><br> f(x) = -1/2√x + 3, x ≥ -3
inna [77]
<span>Find the inverse of the given function.

f(x) = -1/2√x + 3, x ≥ -3

I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3.  If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.

1.  Replace "f(x)" by "y:"  y </span>= -(1/2)sqrt(x) + 3
 2.  Interchange x and y:  x = -(1/2)sqrt(y) + 3
3.  Solve for y:  x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4.  Replace "y" with 

           -1
        f      (x) = sqrt(2[3-x])

Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers.  The domain here is (-infinity,3]
4 0
3 years ago
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A cheetah runs at a speed of 150 kmph. It covers a distance of 750 m in:
posledela
69699696969699696969969696969969699696969969696996969696
5 0
2 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
____ [38]
We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S

A + S = 50
20A + 40S = 1700

Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S

Now substitute 50 - S for A in the second equation.

20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35

Same day ticket costs $35 and advance ticket costs $15
6 0
3 years ago
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