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Ilia_Sergeevich [38]
3 years ago
5

I need help on problem 53

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0
The answer is a fraction with square roots

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What is the linear function equation that best fits the data set?
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2 horses ran from the same place from the at same time one horse ran at 2 miles per second and the other ran at a speed for 18 m
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3 years ago
a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske
Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1600, \pi = 0.4

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0
3 years ago
Convert 0.135 repeating to a fraction
labwork [276]
I think its 135thousanths
135/1000
6 0
3 years ago
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