2 years ago

I need help on problem 53

Mathematics

1 answer:

Brrunno [24]2 years ago

6 0

The answer is a fraction with square roots

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svetoff [14.1K]

Answer:

See attached diagram

Step-by-step explanation:

Triangle ABC has vertices A(9,3), B(-7,-5) and C(-3,7).

The dilation with a scale factor of 1/4 centered at (5, -5) has the rule

$(x,y)\rightarrow \left(\dfrac{1}{4}x+\dfrac{15}{4},\dfrac{1}{4}y-\dfrac{15}{4}\right)$

Then

$A(9,3)\rightarrow A'\left(\dfrac{1}{4}\cdot 9+\dfrac{15}{4},\dfrac{1}{4}\cdot 3-\dfrac{15}{4}\right)=A'(6,-3);$

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Answer:

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Step-by-step explanation:

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This would give us 10 books/2 months.

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Step-by-step explanation:

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