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2 years ago

What were Roman Capitals first used for?

Computers and Technology

2 answers:

OlgaM077 [116]2 years ago

4 0

Used to write inscriptions

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

Square capitals were used to write inscriptions, and less often to supplement everyday handwriting. When written in documents this style is known as Latin book hand. For everyday writing the Romans used a current cursive hand known as Latin cursive. Notable examples of square capitals used for inscriptions are found on the Roman Pantheon, Trajan's Column, and the Arch of Titus, all in Rome. Square capitals are characterized by sharp, straight lines, supple curves, thick and thin strokes, angled stressing and incised serifs. These Roman capitals are also called majuscules, as a counterpart to minuscule letters such as Merovingian and Carolingian.

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A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info

Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0

2 years ago

Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster

weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

int year=0;

cout<<"Enter present population of town A : ";

cin >> townA;

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;

cout<<endl<<"Enter present population of town B : ";

cin >> townB;

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;

{

populationA = townA + (townA * growthA);

populationB = townB + (townB * growthB);

townA = populationA;

townB = populationB;

year++;

}while(populationA < populationB);

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

6 0

3 years ago

In the airline industry, frequent flyer programs, ticket kiosks, and e-ticketing are all examples of capabilities that are _____

crimeas [40]

Answer:

valuable; rare

Explanation:

A valuable capability is that which gives a firm some competitive advantage. Core competencies are the operational activities that a company does best. A business’s core competencies are what distinguish it from other rival companies in its industry. While Rare capabilities are capabilities that a small amount of, if any, competitors possess. Those type of capabilities that are costly or impossible to imitate.

from the above explanation we can deduce that the modern technology implementation in the airline industry has made it possible to have valuable ptograms and softwares for carring out several task which are no longer scarce to procure.

7 0

2 years ago

According to the segment, which of the following should graphic designers maintain?

gogolik [260]

Answer:D

Explanation:

3 0

2 years ago

The total nodal delay includes:

blondinia [14]

Answer:

all of the above

Explanation:

Total nodal delay is the sum of all types of delay.There are basically four types delay that are as following:-

Processing Delay.
Propagation Delay.
Transmission Delay.
Queuing Delay.

T(nodal)=T(processing)+T(propagation)+T(transmission)+T(queuing).

Where T is the delay time.We are given with propagation,transmission and processing.Nodal delay includes these 3 delays.

Hence we conclude that the answer is all of the above.

3 0

2 years ago

Read 2 more answers