Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
<span>2680 * 6.2% = $166
Make sure you add the amount that is supposed to be deducted when you attempt to solve your problems, I'm a visual learner and I usually find it best to write everything out to see where to go next. <3 do well my dear</span>
Step-by-step explanation:
003:
To solve this, we'll be using the Pythagorean theorem, 
004:
For the next couple questions we'll be using a fun rule called SOHCAHTOA, which stands for Sin (Opposite/Hypotenuse) Cos (Adjacent/Hypotenuse) Tan (Opposite/Adjacent). From this we can see that Tan θ is 8/
.
005:
From this rule again, we can tell that sin Ф (Opposite/Hypotenuse) is going to be /15.
Answer:
003:
004: 8/
005: /15
20 because when you divide 12 by 3/5 you get 20 use a calculator
