Answer:
Step-by-step explanation:
(a) The length and breadth of the playground as measured by the surveyor are 20 m and 13 m respectively to nearest metre.
Since the actual length is x m and breadth is y m, then;
i. x ≥ 20 m or x ≤ 20 m
ii. y ≥ 13 m or y ≤ 13 m
(b) perimeter of the playground = 2 (length + breadth)
= 2 ( 20 + 13)
= 2 x 33
= 66 m
The range of values of the perimeter = 65.4 m < perimeter < 66.5 m
ii. area of the playground = length x breadth
= 20 x 13
= 260
The range of values of the area = 259.4 < Area < 260.5
Answer:
Step-by-step explanation:
Given: The Holy Roman Empire was a group of regions in Central Europe that was held together by a political union. The Holy Roman Empire was formed in the year 962.
Let x represent any year.
Now, the inequality in terms of x and 962 that is true only for values of x that represent years before the year that the Holy Roman Empire formed is given by :-
The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive
So as x approaches infinity then y approaches infinity
as x approaches -infinity then y approaches infinity
The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.
Now we check the x intercepts of the first graph
x intercepts of first graph is -4 and 2
Plug in -4 for x in f(x) and check whether we get 0
Now plug in 2 for x and check
So -4 and 2 are the x intercepts that satisfies f(x)
Hence first option is the graph of