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3 years ago

Meadow is growing her hair out. The graph below shows how much her hair has

Mathematics

1 answer:

Kisachek [45]3 years ago

5 0

Answer:

Step-by-step explanation:

answer is B (.50) because it went from 1 to 1.5 to 2 to 2.5 , that means you are adding .5 everytime

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Determine the value of the variable that makes the equation true. 12-b=12.5

dusya [7]

Answer:

B = -.5

Step-by-step explanation:

If B is negative is cancels out the prexisting negative making it positive.

6 0

3 years ago

What’s the answer to 10a - 13a being factored

solmaris [256]

Answer:

a(10 - 13)

Step-by-step explanation:

The only common factor between these numbers is a, as 10 and 13 do not share factors (13 is prime). We can only factor out a.

7 0

3 years ago

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Elena L [17]

Answer:

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4 0

3 years ago

Read 2 more answers

Given the arrangement,

Law Incorporation [45]

Answer:

the flooor length 360 and the floor breadth 4x90=360

Step-by-step explanation:

3 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

4 years ago